A beam of x rays of wavelength 0.10 nm is found to diffract in second order from the face of a LiF crystal at a Bragg angle of 30 ° .The distance between adjacent crystal planes is about:
A)0.10 nm
B)0.20 nm
C)0.25 nm
D)0.30 nm
E)0.40 nm

Question

Quizplus · Accepted Answer

The Bragg's law formula is $n\lambda = 2d\sin\theta$, where $n$ is the order of diffraction, $\lambda$ is the wavelength of the X-rays, $d$ is the distance between the crystal planes, and $\theta$ is the Bragg angle. Given $n = 2$, $\lambda = 0.10$ nm, and $\theta = 30^\circ$, we can solve for $d$. Substituting the given values, we get $2 \times 0.10 = 2d \sin(30^\circ)$. Since $\sin(30^\circ) = 0.5$, the equation simplifies to $0.20 = 2d \times 0.5$, leading to $d = 0.20$ nm.

A Beam of X Rays of Wavelength 0