Electromagnetic radiation with a wavelength of 3.5 *10^-12 m is scattered from stationary electrons and photons that have been scattered through 50° are detected.An electron from which one of these photons was scattered receives an energy of: A)0 J B)1.1 *10^-14 J C)1.9 * 10^-14 J D)2.3 * 10^-14 J E)1.3 * 10^-13 J

Question

Quizplus · Accepted Answer

The energy of a photon with wavelength λ is given by E = hc/λ, where h is Planck's constant and c is the speed of light. 
For the given wavelength, 
λ = 3.5 x 10^-12 m 
E = hc/λ = (6.626 x 10^-34 J s) (3 x 10^8 m/s) / (3.5 x 10^-12 m) = 1.79 x 10^-19 J 
The energy of the photon scattered through 50 degrees is the same as the incident photon. 
Therefore, the energy received by the electron is the difference between the energies of the incident and scattered photon. 
ΔE = Eincident - Escattered = (1.79 x 10^-19 J) - (1.1 x 10^-14 J) = -1.098 x 10^-14 J 
Since the electron is stationary, it does not receive any kinetic energy from the scattered photon, and the answer is A) 0 J. 
However, this is not one of the options, so the closest option is B) 1.1 x 10^-14 J.

Electromagnetic Radiation with a Wavelength of 3