An electron is trapped in a deep well with a width of 0.3 nm.If it is in the state with quantum number n = 3 its kinetic energy is: A)6.0 * 10^-28 J B)1.8 *10^-27 J C)6.7*10^-19 J D)2.0 *10^-18 J E)6.0 * 10^-18 J

Question

Quizplus · Accepted Answer

The kinetic energy of an electron in a deep well with a width of 0.3 nm and quantum number n = 3 is given by:$$T = \frac{h^2}{8mL^2}n^2$$where h is the Planck constant, m is the mass of the electron, L is the width of the well, and n is the quantum number.Plugging in the given values, we get:$$T = \frac{(6.626 	imes 10^{-34} 	ext{ J s})^2}{8(9.109 	imes 10^{-31} 	ext{ kg})(0.3 	imes 10^{-9} 	ext{ m})^2}(3)^2 = 6.0 	imes 10^{-18} 	ext{ J}$$Therefore, the correct answer is E.

An Electron Is Trapped in a Deep Well with a Width