If the fatty acid 12:1 ^$\Delta$ ⁷ is completely catabolized to CO₂ and H₂O, what would be the gross yield of ATP?

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The fatty acid described is a 12-carbon fatty acid with one double bond. Complete catabolism of such a fatty acid through β-oxidation and subsequent processing via the citric acid cycle and electron transport chain yields a specific amount of ATP. For each 2-carbon unit (acetyl-CoA) entering the citric acid cycle, 10 ATPs are produced (3 NADH = 7.5 ATP, 1 FADH2 = 1.5 ATP, and 1 GTP = 1 ATP). The double bond reduces the ATP yield by 1.5 ATP because one FADH2 is not formed in the first cycle of β-oxidation. Thus, for a 12-carbon fatty acid, 5 acetyl-CoA units are produced, yielding 50 ATP from the citric acid cycle, plus 4 ATP directly from β-oxidation (1 ATP is used up per cycle, but the first cycle is different due to the double bond, so only 4 cycles are fully ATP-generating), minus 1.5 ATP for the double bond adjustment, plus 12 ATP from the 6 NADH produced during β-oxidation (2.5 ATP per NADH), totaling 78.5 ATP.

If the Fatty Acid 12:1 Δ\DeltaΔ 7 Is Completely Catabolized to CO2 and H2O, What

If the Fatty Acid 12:1 ^$\Delta$ ⁷ Is Completely Catabolized to CO₂ and H₂O, What