In the first step of fatty acid oxidation, the fatty acid (R-COOH) is converted to its coenzyme A derivative in the following reaction:
R-COOH + ATP + CoA-SH $\rightarrow$ R-CO-S-CoA + AMP + PP_i
The standard free-energy change ( $\Delta$ G'°) for this reaction is -15 kJ/mol
What will tend to make the reaction even more favorable when it takes place within a cell?

Question

In the first step of fatty acid oxidation, the fatty acid (R-COOH) is converted to its coenzyme A derivative in the following reaction:
R-COOH + ATP + CoA-SH

\rightarrow

R-CO-S-CoA + AMP + PP_i
The standard free-energy change (

\Delta

G'°) for this reaction is -15 kJ/mol
What will tend to make the reaction even more favorable when it takes place within a cell?

Quizplus · Accepted Answer

The Answer of In the first step of fatty acid oxidation, the fatty acid (R-COOH) is converted to its coenzyme A derivative in the following reaction: R-COOH + ATP + CoA-SH $\rightarrow$ R-CO-S-CoA + AMP + PP_i The standard free-energy change ($\Delta$G'°) for this reaction is -15 kJ/mol What will tend to make the reaction even more favorable when it takes place within a cell?

In the First Step of Fatty Acid Oxidation, the Fatty →\rightarrow→

In the First Step of Fatty Acid Oxidation, the Fatty $\rightarrow$