glucose 6-phosphate $\rightarrow$ glucose + P_i
$\Delta$ G'° = -13.8 kJ/mol
show how you would calculate the standard free-energy change ( $\Delta$ G'°) for the reaction:

Question

glucose 6-phosphate $\rightarrow$ glucose + P_i $\Delta$G'° = -13.8 kJ/mol show how you would calculate the standard free-energy change ($\Delta$G'°) for the reaction:

Quizplus · Accepted Answer

The Answer of glucose 6-phosphate $\rightarrow$ glucose + P_i $\Delta$G'° = -13.8 kJ/mol show how you would calculate the standard free-energy change ($\Delta$G'°) for the reaction:

Glucose 6-Phosphate →\rightarrow→ Glucose + Pi Δ\DeltaΔ G'° = -138 KJ/mol Show How You Would Calculate the Standard Free-Energy

Glucose 6-Phosphate $\rightarrow$ Glucose + P_i $\Delta$ G'° = -138 KJ/mol
Show How You Would Calculate the Standard Free-Energy