A sample of 2,007 American adults was asked how they viewed China, with 17% of respondents calling the country "unfriendly" and 6% of respondents indicating the country was "an enemy." Construct a 99% confidence interval of the proportion of American adults who viewed China as "an enemy."
A) [0.0463, 0.0737]
B) [0.0476, 0.0724]
C) [0.0512, 0.0688]
D) [0.0597, 0.0603]

Question

Quizplus · Accepted Answer

To construct a 99% confidence interval for the proportion of American adults who viewed China as "an enemy," we use the formula for a confidence interval for a proportion: $p \pm z*\sqrt{\frac{p(1-p)}{n}}$, where $p$ is the sample proportion, $z$ is the z-score corresponding to the confidence level (for 99%, $z \approx 2.576$), and $n$ is the sample size. Here, $p = 0.06$ (6%), $n = 2007$. Plugging these values into the formula gives us the interval $[0.0463, 0.0737]$.

A Sample of 2,007 American Adults Was Asked How They