On a particular production line, the likelihood that a light bulb is defective is 5%. Ten light bulbs are randomly selected. What is the probability that two light bulbs will be defective?
A) 0.0105
B) 0.0746
C) 0.3151
D) 0.5987

Question

Quizplus · Accepted Answer

This is a binomial probability problem where n = 10 (number of trials), k = 2 (number of successes), p = 0.05 (probability of success on a single trial), and q = 1 - p = 0.95 (probability of failure). The binomial probability formula is P(X = k) = (nCk) * p^k * q^(n-k), where nCk is the combination of n items taken k at a time. Plugging in the values: P(X = 2) = (10C2) * (0.05)^2 * (0.95)^8, which calculates to approximately 0.0746.

On a Particular Production Line, the Likelihood That a Light