Al's production function for deer is f(x₁, x₂)= (2x₁ + x₂)^1/2, where x₁ is the amount of plastic and x₂ is the amount of wood used.If the cost of plastic is $8 per unit and the cost of wood is $1 per unit, then the cost of producing 7 deer is A)$49. B)$119. C)$196. D)$7. E)$28.

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The cost of producing 7 deer is the minimum cost of producing 7 deer, which is found by solving the following optimization problem:min c = 8x₁ + x₂subject to f(x₁, x₂) = 7The Lagrangian for this problem is:L = 8x₁ + x₂ + λ[(2x₁ + x₂)^1/2 - 7]Taking the partial derivatives of L with respect to x₁, x₂, and λ, we get:∂L/∂x₁ = 8 + λ(2x₁ + x₂)^-1/2 = 0∂L/∂x₂ = 1 + λ(2x₁ + x₂)^-1/2 = 0∂L/∂λ = (2x₁ + x₂)^1/2 - 7 = 0Solving these equations, we get:x₁ = 4x₂ = 3λ = 1/4Therefore, the cost of producing 7 deer is:c = 8x₁ + x₂ = 8(4) + 3 = $35

Al's Production Function for Deer Is F(x1, X2)= (2x1

Al's Production Function for Deer Is F(x₁, X₂)= (2x₁