A simple random sample of 60 blood donors is taken to estimate the proportion of donors with type A blood with a 95% confidence interval.In the sample,there are 10 people with type A blood.What is the margin of error for this confidence interval?
A)0.048
B)0.079
C)0.094
D)1.96

Question

Quizplus · Accepted Answer

The margin of error is calculated using the formula for a proportion: ME = Z * sqrt[(p(1-p))/n], where Z is the Z-score for a 95% confidence level (1.96), p is the sample proportion (10/60), and n is the sample size (60). Plugging in these values gives a margin of error of approximately 0.094.

A Simple Random Sample of 60 Blood Donors Is Taken