Considering the limiting reactant concept,how many moles of copper(I) sulfide are produced from the reaction of 0.500 mol of copper and 0.750 mol of sulfur? 2 Cu(s) + S(s)
Cu2S(s)
A) 0.250 mol
B) 0.375 mol
C) 0.500 mol
D) 0.750 mol
E) none of the above
Correct Answer:
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