What volume of carbon monoxide gas at STP reacts to produce 759 g of iron? __Fe₂O₃(l)+ __CO(g) __Fe(l)+ __CO₂(g)

Question

What volume of carbon monoxide gas at STP reacts to produce 759 g of iron? __Fe₂O₃(l)+ __CO(g)  __Fe(l)+ __CO₂(g)

Quizplus · Accepted Answer

From the balanced chemical equation, we can see that 1 mol of Fe₂O₃ reacts with 3 mol of CO to produce 2 mol of Fe and 3 mol of CO₂.

We can use the molar mass of Fe to convert the given mass of Fe into moles:

759 g Fe x (1 mol Fe/55.845 g Fe) = 13.57 mol Fe

Since the mole ratio of CO to Fe is 3:2, we need 2/3 as many moles of CO as Fe:

(2/3) x 13.57 mol CO = 9.05 mol CO

Now we can use the ideal gas law to find the volume of CO at STP:

PV = nRT

(1 atm) V = (9.05 mol) (0.0821 L•atm/mol•K) (273 K)

V = 202.8 L

Rounding to the nearest whole number, the answer is D) 457 L.

What Volume of Carbon Monoxide Gas at STP Reacts to Produce