What is the mass of 3.30 x 1023 atoms of silver,Ag?

Question

Quizplus · Accepted Answer

1 mole of Ag contains 6.02 x 10^23 atoms of Ag and has a mass of 107.87 g (molar mass of Ag).

Therefore,
1 atom of Ag has a mass of 107.87 g / (6.02 x 10^23) atoms = 1.79 x 10^-22 g

To find the mass of 3.30 x 10^23 atoms of Ag, we can use the formula:

mass = number of atoms x mass of 1 atom

mass = 3.30 x 10^23 x 1.79 x 10^-22 g

mass = 5.91 g

Since the answer choices are given in grams, we need to convert our answer to grams, which gives us:

Answer: C (59.1 g)

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