What is the volume occupied by 0.750 g of nitrogen gas,N₂,at STP?

Question

Quizplus · Accepted Answer

The volume occupied by 0.750 g of nitrogen gas, N₂, at STP can be calculated using the ideal gas law:PV = nRTwhere P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.At STP, the pressure is 1 atm, the temperature is 273.15 K, and the ideal gas constant is 0.0821 L·atm/(mol·K).The number of moles of nitrogen gas can be calculated using the molar mass of nitrogen, which is 28.01 g/mol:n = m/M = 0.750 g / 28.01 g/mol = 0.0268 molSubstituting these values into the ideal gas law, we get:V = nRT/P = (0.0268 mol)(0.0821 L·atm/(mol·K))(273.15 K) / 1 atm = 0.600 LTherefore, the volume occupied by 0.750 g of nitrogen gas at STP is 0.600 L.

What Is the Volume Occupied by 0