If 0.391 g of potassium metal reacts with 1.269 g of iodine,what is the mass of potassium iodide produced?

Question

Quizplus · Accepted Answer

The reaction between potassium (K) and iodine (I2) to form potassium iodide (KI) is a stoichiometric reaction where 2 moles of potassium react with 1 mole of iodine to produce 2 moles of potassium iodide. The mass of potassium iodide produced is the sum of the masses of potassium and iodine that reacted, which is 0.391 g + 1.269 g = 1.660 g.

If 0391 G of Potassium Metal Reacts with 1