A sheet of aluminum foil has a volume of 0.555 cm3.If the foil measures 10.0cm by 10.0 cm,what is the thickness of the foil?

Question

Quizplus · Accepted Answer

The volume of the foil is equal to its area (10.0 cm x 10.0 cm) multiplied by its thickness (T):
0.555 cm3 = (10.0 cm x 10.0 cm) x T
T = 0.555 cm3 / 100 cm2
T = 0.00555 cm = 0.005 55 cm
Therefore, the thickness of the foil is 0.005 55 cm. The correct answer is B.

A Sheet of Aluminum Foil Has a Volume of 0