In 1996 a team of German physicists created an atom of Element 112.If the atom had a mass number of 277,and a neutron was released from the collision of a projectile and a Pb-208 target,what was the projectile?

Question

Quizplus · Accepted Answer

The projectile was Zn-70. The collision involved a Pb-208 target and the release of a neutron, leading to an atom of Element 112 with a mass number of 277. The equation for the reaction is: Pb-208 + Zn-70 → Element 112-277 + neutron. This means the total mass number before the reaction (208 from Pb + 70 from Zn) equals the mass number after the reaction (277 from the new element + 1 from the neutron), confirming Zn-70 as the correct projectile.

In 1996 a Team of German Physicists Created an Atom