What is the oxidation number of bromine in NaBrO₃?

Question

Quizplus · Accepted Answer

In the compound NaBrO₃, sodium always has an oxidation state of +1. Oxygen always has an oxidation state of -2, therefore the three oxygen atoms in NaBrO₃ contribute to an oxidation number of -6. To find the oxidation number of bromine, we can use the fact that the sum of the oxidation numbers in a compound must equal the overall charge of the compound, which is 0 in this case.

Let x be the oxidation number of bromine in NaBrO₃. Then:

(+1) + x + (-6) = 0 
x - 5 = 0 
x = +5

Therefore, the oxidation number of bromine in NaBrO₃ is +5.

What Is the Oxidation Number of Bromine in NaBrO₃