If 0.600 mol of A reacts with 1.40 mol of B according to the following equation,how many moles of excess reactant remain after complete reaction? A(g)+ 2 B(g)→ 3 C(g)

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Quizplus · Accepted Answer

According to the stoichiometry of the reaction, 1 mole of A reacts with 2 moles of B. Therefore, 0.600 mol of A would require 1.2 mol of B to completely react. Since there are 1.40 mol of B available, 1.40 - 1.2 = 0.2 mol of B would remain unreacted after the reaction is complete.

If 0600 Mol of a Reacts with 1