If 20.0 mL of 0.200 M H₂SO₄ is titrated with 0.100 M NaOH,what volume of sodium hydroxide is required to neutralize the acid? H₂SO₄(aq)+ 2 NaOH(aq)→ Na₂SO₄(aq)+ 2 H₂O(l)

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Quizplus · Accepted Answer

First, calculate the moles of $H_2SO_4$: $20.0 \, \text{mL} \times 0.200 \, \text{M} = 0.004 \, \text{moles}$. Since the reaction ratio of $H_2SO_4$ to $NaOH$ is 1:2, $0.004 \, \text{moles}$ of $H_2SO_4$ requires $0.008 \, \text{moles}$ of $NaOH$. To find the volume of $0.100 \, \text{M} \, NaOH$ needed: $0.008 \, \text{moles} / 0.100 \, \text{M} = 80.0 \, \text{mL}$.

If 200 ML of 0