An ammonia solution is 6.00 M and the density is 0.950 g/mL.What is the mass/mass percent concentration of NH₃ (17.04 g/mol)?

Question

Quizplus · Accepted Answer

The mass/mass percent concentration ($w/w\%$) of NH₃ can be calculated by first determining the mass of NH₃ in 1 L of solution and then finding the mass of the solution itself. Given that the solution is 6.00 M, there are 6.00 moles of NH₃ in 1 L (1000 mL) of solution. The mass of NH₃ is then $6.00 \, \text{moles} \times 17.04 \, \text{g/mole} = 102.24 \, \text{g}$. The mass of 1 L of solution is $1000 \, \text{mL} \times 0.950 \, \text{g/mL} = 950 \, \text{g}$. The mass/mass percent concentration is $\frac{102.24 \, \text{g}}{950 \, \text{g}} \times 100\% = 10.8\%$.

An Ammonia Solution Is 6