What is the mass of water required to prepare 250.0 g of 10.0% copper(II)sulfate solution?

Question

Quizplus · Accepted Answer

Assuming that the percentage refers to mass percentage:

- 10.0% of a 250.0 g solution is copper(II) sulfate
- This means there is 0.1 x 250.0 g = 25.0 g of copper(II) sulfate in the solution
- To prepare this solution, we need to dissolve the 25.0 g of copper(II) sulfate in a certain amount of water
- The final mass of the solution is 250.0 g, so the mass of water must be 250.0 g - 25.0 g = 225.0 g

Therefore, the mass of water required is 225 g.

What Is the Mass of Water Required to Prepare 250