What is the volume of 6.00 M nitric acid that contains 6.302 g of HNO₃ solute (63.02 g/mol)?

Question

Quizplus · Accepted Answer

First, we need to use the formula to convert grams of solute to moles:
moles of HNO₃ = 6.302 g / 63.02 g/mol = 0.100 mol
Next, we can use the concentration and volume formula to solve for volume:
M1V1 = n2/M2
Where:
M1 = 6.00 M (given concentration)
V1 = volume (unknown)
n2 = 0.100 mol (from above calculation)
M2 = molarity of HNO₃ (same as M1, since HNO₃ is the only solute)
Solve for V1:
V1 = n2/M1 = 0.100 mol / 6.00 M = 0.0167 L
Finally, convert liters to milliliters:
V1 = 0.0167 L * 1000 mL/L = 16.7 mL.

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