Given the values for Br (2.8)and F (4.0),calculate the electronegativity difference in a bromine monofluoride bond,BrF.

Question

Quizplus · Accepted Answer

To calculate electronegativity difference, we subtract the electronegativity of the smaller atom (Br) from the electronegativity of the larger atom (F).

Electronegativity difference = electronegativity of F - electronegativity of Br
Electronegativity difference = 4.0 - 2.8
Electronegativity difference = 1.2

Therefore, the answer is A) 1.2.

Given the Values for Br (2