Calculate the heat absorbed when 10.0 g of ice at 0 °C melts to water at the same temperature.The specific heat of water is 1.00 cal/(g x °C);the heat of fusion is 80.0cal/g;and the heat of vaporization is 540.0 cal/g.

Question

Quizplus · Accepted Answer

First, we need to calculate the heat required to melt the ice, using the heat of fusion:

q = m∙ΔHf = 10.0 g∙80.0 cal/g = 800 cal

Next, we need to calculate the heat required to raise the temperature of the resulting water from 0°C to 0°C, using the specific heat of water:

q = m∙c∙ΔT = 10.0 g∙1.00 cal/(g∙°C)∙(0°C-0°C) = 0 cal

Therefore, the total heat absorbed is:

q = 800 cal + 0 cal = 800 cal = 8.00 x 102 cal

The best choice is D, because it is the only one with the correct units and magnitude.

Calculate the Heat Absorbed When 10