Calculate the heat required to convert 10.0 g of water at 100 °C to steam at 100 °C.The specific heat of water is 1.00 cal/(g x °C);the heat of fusion is 80.0 cal/g;and the heat of vaporization is 540.0 cal/g.

Question

Quizplus · Accepted Answer

First, calculate the heat required to raise the temperature of the water from 100 °C to 100 °C (since it is already at the boiling point).

Q = m x c x ΔT
Q = 10.0 g x 1.00 cal/(g x °C) x 0 °C
Q = 0 cal

The heat of fusion is not relevant in this case since we are not dealing with a phase change from solid to liquid.

Next, calculate the heat required to vaporize the water.

Q = m x Hvap
Q = 10.0 g x 540.0 cal/g
Q = 5.40 x 10^3 cal

Add the two heats together:

Qtotal = 0 cal + 5.40 x 10^3 cal
Qtotal = 5.40 x 10^3 cal

Therefore, the answer is E.

Calculate the Heat Required to Convert 10