Calculate the heat required to convert 10.0 g of ice at 0.0 °C to steam at 100.0 °C.The specific heat of water is 1.00 cal/(g x °C);the heat of fusion is 80.0 cal/g;and the heat of vaporization is 540.0 cal/g.

Question

Quizplus · Accepted Answer

The total heat required includes the heat to melt the ice, heat the water, and vaporize it: (10 g x 80 cal/g) + (10 g x 100 cal/g x 1 cal/g°C) + (10 g x 540 cal/g) = 7200 cal.

Calculate the Heat Required to Convert 10