A bakery is considering hiring another clerk to better serve customers. To help with this decision, records were kept to determine how many customers arrived in 10-minute intervals. Based on 100 10-minute intervals, the following probability distribution and random number assignments developed.
$$\begin{array} { | c | c | c | }
\hline \begin{array} { c }
\text { Number of } \
\text { Arrivals }
\end{array} & \text { Probability } & \begin{array} { c }
\text { Random } \
\text { numbers }
\end{array} \
\hline 6 & .1 & .01 - .10 \
\hline 7 & .3 & .11 - .40 \
\hline 8 & .3 & .41 - .70 \
\hline 9 & .2 & .71 - .90 \
\hline 10 & .1 & .91 - .00 \
\hline
\end{array}$$
-Suppose the next three random numbers were .08, .50 and .69. How many customers would have arrived during this 30-minute period?
A) 22
B) 23
C) 24
D) 25

Question

A bakery is considering hiring another clerk to better serve customers. To help with this decision, records were kept to determine how many customers arrived in 10-minute intervals. Based on 100 10-minute intervals, the following probability distribution and random number assignments developed.
 $$\begin{array} { | c | c | c | } 
\hline \begin{array} { c } 
\text { Number of } \
\text { Arrivals }
\end{array} & \text { Probability } & \begin{array} { c } 
\text { Random } \
\text { numbers }
\end{array} \
\hline 6 & .1 & .01 - .10 \
\hline 7 & .3 & .11 - .40 \
\hline 8 & .3 & .41 - .70 \
\hline 9 & .2 & .71 - .90 \
\hline 10 & .1 & .91 - .00 \
\hline
\end{array}$$
-Suppose the next three random numbers were .08, .50 and .69. How many customers would have arrived during this 30-minute period?
A) 22
B) 23
C) 24
D) 25

Quizplus · Accepted Answer

The random numbers .08, .50, and .69 correspond to 6, 8, and 8 customers arriving in each 10-minute interval, respectively. Adding these together gives 6 + 8 + 8 = 22 customers in the 30-minute period.

A Bakery Is Considering Hiring Another Clerk to Better Serve