A multiple-channel queuing system with a Poisson arrival rate and exponential service time has an average arrival rate of 4 customers per hour and an average service time of 18 minutes per customer. What is the minimum number of servers required to avoid an overloaded system?
A) 1
B) 2
C) 3
D) 4

Question

Quizplus · Accepted Answer

The minimum number of servers required to avoid an overloaded system is 2. This is because the average arrival rate is 4 customers per hour and the average service time is 18 minutes per customer. This means that the average number of customers in the system is 4 * 18 / 60 = 1.2. Therefore, the minimum number of servers required to avoid an overloaded system is 2.

A Multiple-Channel Queuing System with a Poisson Arrival Rate and Exponential