If the random variable x is normally distributed with a mean of 88 and a standard deviation of 12, what is the value of P(x 96)?
A) 0.1243
B) 0.2486
C) 0.2514
D) 0.4972

Question

If the random variable x is normally distributed with a mean of 88 and a standard deviation of 12, what is the value of P(x  96)?
A) 0.1243 
B) 0.2486 
C) 0.2514 
D) 0.4972

Quizplus · Accepted Answer

To find P(x < 96), we need to standardize the variable x:

z = (x - μ) / σ

z = (96 - 88) / 12 = 0.67

Using a standard normal distribution table, we can find the probability that z is less than 0.67:

P(z < 0.67) = 0.2514

Therefore, the answer is C.

If the Random Variable X Is Normally Distributed with a Mean