Suppose that the z-value for a given value x of the random variable X is z = 1.96, and that the distribution of X is normally distributed with a mean of 60 and a standard deviation of 6. To what x-value does this z-value correspond?
A) 71.76
B) 67.96
C) 61.96
D) 48.24

Question

Quizplus · Accepted Answer

The z-value formula is z = (x - mean) / standard deviation. Solving for x gives x = z * standard deviation + mean = 1.96 * 6 + 60 = 71.76.

Suppose That the Z-Value for a Given Value X of the Random