If the specific rotation of the (R)-enantiomer of a compound is -4.8^o, what will the specific rotation be for the (S)-enantiomer of the compound? A) +4.8° B) -4.8° C) 0° D) There is no way to tell.

Question

Quizplus · Accepted Answer

The specific rotation of an enantiomer is equal in magnitude but opposite in sign to its mirror image. Therefore, the (S)-enantiomer will have a specific rotation of +4.8°.

If the Specific Rotation of the (R)-Enantiomer of a Compound