Assuming that the volumes are additive, what volume of water must be added to 35.0 mL of 15.0%(w/v) KOH to make a solution which is 10.0%(w/v)?
A) 15.0 mL
B) 17.5 mL
C) 23.3 mL
D) 52.5 mL

Question

Quizplus · Accepted Answer

To find the volume of water to add, use the formula: C1V1 = C2V2. Here, C1 = 15.0%, V1 = 35.0 mL, C2 = 10.0%. Solving for V2 gives V2 = (C1V1)/C2 = (15.0% * 35.0 mL) / 10.0% = 52.5 mL. The volume of water to add is V2 - V1 = 52.5 mL - 35.0 mL = 17.5 mL.

Assuming That the Volumes Are Additive, What Volume of Water