A vessel under 2.015 atm pressure contains nitrogen, N₂, and water vapor, H₂O. The partial pressure of N₂ is 1.908 atm. What is the partial pressure of the water vapor?

Question

Quizplus · Accepted Answer

The total pressure in the vessel is 2.015 atm, and the partial pressure of nitrogen (N₂) is 1.908 atm. Therefore, the partial pressure of the water vapor (H₂O) can be calculated by subtracting the partial pressure of nitrogen from the total pressure: Partial pressure of water vapor = Total Pressure - Partial Pressure of Nitrogen Partial pressure of water vapor = 2.015 atm - 1.908 atm Partial pressure of water vapor = 0.107 atm Therefore, the partial pressure of water vapor is 0.107 atm, which corresponds to choice A.

A Vessel Under 2