When a solution of ammonium chloride, NH4Cl, is added to a solution of lead(II) nitrate, Pb(NO3) 2, a white precipitate of lead chloride, PbCl2, forms. Which of the following is the total ionic equation for this reaction?
A) 2 NH4Cl(aq) + Pb(NO3) 2(aq) → PbCl2(s) + 2 NH4NO3(aq)
B) 2 NH4+(aq) + 2 Cl-(aq) + Pb2+(aq) + 2 NO3-(aq)
→ PbCl2(s) + 2 NH4+(aq) + 2 NO3-(aq)
C) Pb2+(aq) + 2 Cl-(aq) → PbCl2(s)
D) Pb2+(aq) + Cl22-(aq) → PbCl2(s)
Correct Answer:
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