An individual who is heterozygous for two linked genes (with alleles A, a and B, b) is crossed with an a b/a b individual, and among the progeny are the following: 14 A B/a b
36 A b/a b
34 a B/a b
16 a b/a b
What is the frequency of recombination?

Question

Quizplus · Accepted Answer

The frequency of recombination is calculated by adding the recombinant offspring (A b/a b and a B/a b) and dividing by the total number of offspring. Here, (36 + 34) / (14 + 36 + 34 + 16) = 70 / 100 = 0.70 or 70%. However, since recombination frequency is the percentage of recombinant offspring, and the question seems to have a misunderstanding in the options provided, the correct interpretation of the given options leads to recognizing a mistake in the question's presentation of options. The correct calculation method shows a 70% recombination frequency, but none of the options correctly reflects this. Given the options, the closest correct approach to interpreting the question as intended would be to recognize the error and understand that the recombination frequency is indeed 70%, which is not accurately represented in the provided choices.

An Individual Who Is Heterozygous for Two Linked Genes (With