In Jabberwocks, flame eyes (F) are dominant to blue eyes (f) and burbling (B) is dominant to whistling (b). Jabberwock geneticists suspect that the two genes are linked in one of the autosomes. They mate a true-breeding, flame-eyed, burbling female with a true-breeding, blue-eyed, whistling male. They then remove a sample of gametes from one of the resulting offspring. If the genes are linked, which of the following is/are a recombinant gamete genotype?

Question

Quizplus · Accepted Answer

If the genes are linked, then the combination of alleles of each parent will be inherited together in the offspring. The parental genotypes are FFBB and ffbb. The offspring will be FfBb, which means that the gene F is on the same chromosome as B, and f is on the same chromosome as b. Therefore, a recombinant gamete genotype would have a combination of alleles that are different from the parental combination, which would be Fb or fB. The options A and C are parental gametes, and option E is incorrect because there are recombinant gametes in this cross.

In Jabberwocks, Flame Eyes (F) Are Dominant to Blue Eyes