The fruit fly cross shown here analyzes the transmission of two genes in the X chromosome. The male parent has mutant alleles for both the white gene (w-) and the crossveinless gene (cv-) . The female parent has nonmutant forms of these genes (w+ and cw+) . A cross between siblings of the F1 generation-a red-eyed, crossveined female and a red-eyed, crossveined male-generates F2 progeny. Examine the genotype of the F2 male progeny. Notice that the progeny fall into two groups. Refer to the figure below when answering the following question. The numbers of male F2 progeny with each of the four observed phenotypes are as follows:
Red-eyed, crossveined = 357
White-eyed, crossveinless = 341
Red-eyed, crossveinless = 52
White-eyed crossveined = 45
What is the map distance between the genes w and cv? 
A) 97
B) 12.2
C) 341
D) 357
E) 13.9
Correct Answer:
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