You cross a true-breeding stock of black (BB) mice with skinny (SS) toes to a stock of white (bb) mice with fat (ss) toes. From this, you produce an F₁ generation of black mice with skinny toes (Bb,Ss). If the single genes responsible for coat color and toe appearance do not sort independently, then you would expect to see: A)more than 75% of your F₂ black mice with skinny toes. B)more than 25% of your F₂ black mice with fat toes.

Question

Quizplus · Accepted Answer

If the genes do not sort independently, they are likely linked, meaning they are located close to each other on the same chromosome. This linkage would result in a higher frequency of parental phenotypes (black with skinny toes) in the F2 generation, leading to more than 75% of black mice having skinny toes.

You Cross a True-Breeding Stock of Black (BB) Mice with Skinny