Consider a gene with six alleles A₁, A₂, A₃, A₄, A₅, and A₆. How many distinct heterozygous genotypes are possible? A)3 B)6 C)9 D)12 E)15

Question

Quizplus · Accepted Answer

For a gene with six alleles, the number of distinct heterozygous genotypes can be calculated using the combination formula nC2, where n is the number of alleles. Here, n=6, so the calculation is 6C2 = (6*5)/(2*1) = 15.

Consider a Gene with Six Alleles A1, A2, A3, A4

Consider a Gene with Six Alleles A₁, A₂, A₃, A₄