Consider a gene with four alleles A₁, A₂, A₃, and A₄. If the cross A₁A₂ × A₂A₂ yields two offspring, what is the probability that the offspring have the same genotype? A)1/8 B)1/4 C)1/3 D)1/2 E)3/4

Question

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The possible genotypes from the cross A₁A₂ × A₂A₂ are A₁A₂ and A₂A₂. The probability of both offspring having the same genotype is the probability of both being A₂A₂ (1/2 * 1/2 = 1/4) plus the probability of both being A₁A₂ (1/2 * 1/2 = 1/4), totaling 1/4 + 1/4 = 1/2.

Consider a Gene with Four Alleles A1, A2, A3, and A4

Consider a Gene with Four Alleles A₁, A₂, A₃, and A₄