What is the percent yield if 52 g of ammonia produce 45 g of NO? NH₃ + O₂ → NO + H₂O

Question

Quizplus · Accepted Answer

To find the percent yield, we need to compare the actual yield (which is given as 45 g) to the theoretical yield (which we can calculate from the balanced equation). The balanced equation tells us that 4 mol of NH₃ produce 4 mol of NO. So, the theoretical yield of NO from 52 g of NH₃ would be:
(52 g NH₃) / (17.03 g/mol NH₃) x (1 mol NO / 4 mol NH₃) x (30.01 g/mol NO) = 44.9 g NO (rounded to 3 significant figures)
Now we can calculate the percent yield:
(actual yield / theoretical yield) x 100% = (45 g / 44.9 g) x 100% = 100.2%
Since percent yield cannot be more than 100%, we need to round down to the nearest whole number. Therefore, the percent yield is 49%.

What Is the Percent Yield If 52 G of Ammonia