0.68 g of sulfur combine with 1.51 g of chlorine. The empirical formula of this compound is ________.

Question

Quizplus · Accepted Answer

1. Convert the given masses to moles:
Sulfur: 0.68 g / 32.06 g/mol = 0.0212 mol
Chlorine: 1.51 g / 35.45 g/mol = 0.0426 mol
2. Divide each of the mole values by the smallest number of moles to get the mole ratio:
Sulfur: 0.0212 mol / 0.0212 mol = 1
Chlorine: 0.0426 mol / 0.0212 mol = 2
3. Round to the nearest whole number to get the empirical formula:
SCl₂

068 G of Sulfur Combine with 1