Calculate the equilibrium concentration of N₂ for the following reaction. + The equilibrium constant Keq is 0.055 and the concentrations of and are 1.20 M and 0.225 M, respectively.

Question

Calculate the equilibrium concentration of N₂ for the following reaction.  +    The equilibrium constant Keq is 0.055 and the concentrations of  and  are 1.20 M and 0.225 M, respectively.

Quizplus · Accepted Answer

The equation given in the question is:

11eab3b7_63f0_2200_be6e_3dfa3f82c61a_TB6848_11 + 11eab3b7_63f0_2201_be6e_4525ea938c06_TB6848_11 ⇌ 11eab3b7_63f0_2202_be6e_556a239ffb92_TB6848_11 + 11eab3b7_63f0_2203_be6e_2147793c5d07_TB6848_11

We can write the equilibrium constant expression as:

Keq = [11eab3b7_63f0_2202_be6e_556a239ffb92_TB6848_11][11eab3b7_63f0_2203_be6e_2147793c5d07_TB6848_11] / ([11eab3b7_63f0_2200_be6e_3dfa3f82c61a_TB6848_11][11eab3b7_63f0_2201_be6e_4525ea938c06_TB6848_11])

We are given the value of Keq and the initial concentrations of two of the reactants, [11eab3b7_63f0_2200_be6e_3dfa3f82c61a_TB6848_11] and [11eab3b7_63f0_2201_be6e_4525ea938c06_TB6848_11], we can assume that the initial concentration of [11eab3b7_63f0_2202_be6e_556a239ffb92_TB6848_11] and [11eab3b7_63f0_2203_be6e_2147793c5d07_TB6848_11] is 0.

Let's substitute the values in the equilibrium constant expression:

0.055 = (x)(x) / ([11eab3b7_63f0_4914_be6e_857965ada9f2_TB6848_11] - x)([11eab3b7_63f0_4915_be6e_ddb46e502a69_TB6848_11] - x)

where x is the equilibrium concentration of [11eab3b7_63f0_2202_be6e_556a239ffb92_TB6848_11] and [11eab3b7_63f0_2203_be6e_2147793c5d07_TB6848_11].

Now, solving for x, we get:

x = 0.533 M

Therefore, the equilibrium concentration of N₂ is 0.533 M, which is option B.

Calculate the Equilibrium Concentration of N₂ for the Following Reaction