If the solubility product of tin(II) carbonate is 1.03 × 10^-9, the molar solubility is 3.21 × 10^-5 M.

Question

Quizplus · Accepted Answer

The molar solubility of tin(II) carbonate is calculated using the solubility product constant (Ksp), which is provided in the question as 1.03 × 10-9. The equation for the dissolution of tin(II) carbonate is:

SnCO3(s) ⇌ Sn2+(aq) + CO32-(aq)

The Ksp expression is written as:

Ksp = [Sn2+][CO32-]

Since tin(II) carbonate dissociates into one tin ion and one carbonate ion in solution, the molar solubility of tin(II) carbonate can be calculated using the Ksp value:

Ksp = [3.21 × 10-5][3.21 × 10-5]
1.03 × 10-9 = 1.03 × 10-9

Therefore, the given molar solubility value is correct, and the answer is A.

If the Solubility Product of Tin(II) Carbonate Is 1