10.0 mL of 0.50 M sulfuric acid neutralizes ________ mL of 0.50 M ammonium hydroxide solution.

Question

Quizplus · Accepted Answer

Sulfuric acid (H2SO4) is a strong diprotic acid, meaning it can donate two protons (H+ ions) per molecule, while ammonium hydroxide (NH4OH) is a weak base that can accept only one proton per molecule. The neutralization reaction between them can be represented as: H2SO4 + 2NH4OH → (NH4)2SO4 + 2H2O. This shows that one mole of sulfuric acid reacts with two moles of ammonium hydroxide. Since both solutions have the same molarity (0.50 M), but sulfuric acid can neutralize twice as much ammonium hydroxide by mole, 10.0 mL of 0.50 M sulfuric acid will neutralize 20.0 mL of 0.50 M ammonium hydroxide.

100 ML of 0