A solution prepared by dissolving 24 g potassium sulfate in 150 mL total solution has a molarity of 0.92 M.

Question

Quizplus · Accepted Answer

To calculate the molarity of the solution, we first need to convert the mass of potassium sulfate to moles:

24 g K2SO4 x (1 mole K2SO4 / 174.26 g K2SO4) = 0.1379 moles K2SO4

Next, we need to convert the volume of solution from mL to L:

150 mL = 0.150 L

Now we can calculate the molarity:

Molarity = moles of solute / liters of solution
Molarity = 0.1379 moles / 0.150 L
Molarity = 0.919 M, which is approximately 0.92 M

Therefore, the statement is True.

A Solution Prepared by Dissolving 24 G Potassium Sulfate in 150