Match each sodium salt solution with its corresponding number of sodium ion moles.
-100 mL of 0.2 M sodium cyanide solution

Question

Quizplus · Accepted Answer

0.2 M means there are 0.2 moles of sodium cyanide present in 1 liter (1000 mL) of solution.
Therefore, in 100 mL of 0.2 M sodium cyanide solution, there are:
0.2 moles/L x 0.1 L = 0.02 moles of sodium cyanide.
Since one sodium ion is released per molecule of sodium cyanide dissolved, there are also 0.02 moles of sodium ions present in the solution. Thus, the best choice is B.

Match Each Sodium Salt Solution with Its Corresponding Number of Sodium