Match each mass of solute and molarity of the solution with its corresponding total volume of the solution.
-1.10 M lead(II) nitrate solution containing 437 g of solute

Question

Quizplus · Accepted Answer

The molar mass of lead(II) nitrate (Pb(NO3)2) is approximately 331 g/mol. To find the volume, use the formula: moles = mass/molar mass. Moles = 437 g / 331 g/mol = 1.32 mol. Using the molarity formula: Molarity = moles/volume, 1.10 M = 1.32 mol / volume, solving gives volume ≈ 1.20 L.

Match Each Mass of Solute and Molarity of the Solution