Match each mass of solute and molarity of the solution with its corresponding total volume of the solution.
-0.0510 M H?SO? solution containing 50.0 mg of solute

Question

Quizplus · Accepted Answer

To find the volume of the solution, first convert the mass of the solute (H2SO4) to moles. The molar mass of H2SO4 is approximately 98 g/mol. $50.0 \, \text{mg} = 0.0500 \, \text{g}$. So, the number of moles of H2SO4 is $\frac{0.0500 \, \text{g}}{98 \, \text{g/mol}} = 5.10 \times 10^{-4} \, \text{mol}$. Given the molarity (M) is moles of solute per liter of solution ($M = \frac{\text{moles of solute}}{\text{liters of solution}}$), we can rearrange to find the volume of the solution: $V = \frac{\text{moles of solute}}{M}$. Substituting the given values, $V = \frac{5.10 \times 10^{-4} \, \text{mol}}{0.0510 \, \text{M}} = 0.01 \, \text{L} = 10.0 \, \text{mL}$.

Match Each Mass of Solute and Molarity of the Solution